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    Two chords of a circle meeting at an angle 60° bisect each other. If the length of one chord is 10 cm, the length of the other chord (in cm) is
    Question

    Two chords of a circle meeting at an angle 60° bisect each other. If the length of one chord is 10 cm, the length of the other chord (in cm) is

    A.

    5√3

    B.

    10/√2

    C.

    10/√3

    D.

    10

    Correct option is D

    Solution:
    Step 1: Understanding the Problem
    Two chords of a circle bisect each other at an angle of 60°.
    One chord has a length of 10 cm.
    We need to determine the length of the other chord.
    Step 2: Identifying the Property
    When two chords of a circle bisect each other, they follow a specific geometric rule:

    If two chords bisect each other at an angle θ, their lengths remain equal when the angle is 60°.

    This is because, in a circle, if two chords are divided into equal halves and they intersect at an angle of 60°, the bisected parts are symmetric. Thus, their total lengths remain the same.

    Step 3: Applying the Rule
    Given that one chord has a total length of 10 cm, and both chords bisect each other at 60°, the second chord must also have the same length as the first chord.
    Therefore, the second chord also measures 10 cm.
    Final Answer:
    The correct answer is (d) 10 cm.

    Key Takeaways:
    When two chords bisect each other at 60°, they always have equal lengths.
    Since the given chord length is 10 cm, the second chord must also be 10 cm.
    This is a fundamental property of intersecting chords in a circle when bisected at 60°.
    Correct Answer: (d) 10








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