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Two chords of a circle meeting at an angle 60° bisect each other. If the length of one chord is 10 cm, the length of the other chord (in cm) is
Question

Two chords of a circle meeting at an angle 60° bisect each other. If the length of one chord is 10 cm, the length of the other chord (in cm) is

A.

5√3

B.

10/√2

C.

10/√3

D.

10

Correct option is D

Solution:
Step 1: Understanding the Problem
Two chords of a circle bisect each other at an angle of 60°.
One chord has a length of 10 cm.
We need to determine the length of the other chord.
Step 2: Identifying the Property
When two chords of a circle bisect each other, they follow a specific geometric rule:

If two chords bisect each other at an angle θ, their lengths remain equal when the angle is 60°.

This is because, in a circle, if two chords are divided into equal halves and they intersect at an angle of 60°, the bisected parts are symmetric. Thus, their total lengths remain the same.

Step 3: Applying the Rule
Given that one chord has a total length of 10 cm, and both chords bisect each other at 60°, the second chord must also have the same length as the first chord.
Therefore, the second chord also measures 10 cm.
Final Answer:
The correct answer is (d) 10 cm.

Key Takeaways:
When two chords bisect each other at 60°, they always have equal lengths.
Since the given chord length is 10 cm, the second chord must also be 10 cm.
This is a fundamental property of intersecting chords in a circle when bisected at 60°.
Correct Answer: (d) 10








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