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Two bulbs A and B are rated 100W and 25W, respectively, at a given voltage. The ratio of resistance of bulb A to that of bulb B is:
Question

Two bulbs A and B are rated 100W and 25W, respectively, at a given voltage. The ratio of resistance of bulb A to that of bulb B is:

A.

4:1

B.

2:1

C.

1:4

D.

1:2

Correct option is C

Correct Answer: (C) 1:4

Explanation:

The resistance R of a bulb is given by the formula:

R=V2PR= \frac{V^2}{P}​​

Where:

  • V is the voltage,
  • P is the power rating.

Let RA and RB​ be the resistances of bulbs A and B, respectively.

Step 1: Calculate the ratio of resistances.

RARB=V2PAV2PB=PBPA\frac{R_A}{R_B} = \frac{\frac{V^2}{P_A}}{\frac{V^2}{P_B}} = \frac{P_B}{P_A}​​

Given:

  • PA=100W,
  • PB=25W.

RARB=25100=14\frac{R_A}{R_B} = \frac{25}{100} = \frac{1}{4}​​

Thus, the ratio of resistance of bulb A to that of bulb B is 1:4.

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