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    Two bulbs A and B are rated 100W and 25W, respectively, at a given voltage. The ratio of resistance of bulb A to that of bulb B is:
    Question

    Two bulbs A and B are rated 100W and 25W, respectively, at a given voltage. The ratio of resistance of bulb A to that of bulb B is:

    A.

    4:1

    B.

    2:1

    C.

    1:4

    D.

    1:2

    Correct option is C

    Correct Answer: (C) 1:4

    Explanation:

    The resistance R of a bulb is given by the formula:

    R=V2PR= \frac{V^2}{P}​​

    Where:

    • V is the voltage,
    • P is the power rating.

    Let RA and RB​ be the resistances of bulbs A and B, respectively.

    Step 1: Calculate the ratio of resistances.

    RARB=V2PAV2PB=PBPA\frac{R_A}{R_B} = \frac{\frac{V^2}{P_A}}{\frac{V^2}{P_B}} = \frac{P_B}{P_A}​​

    Given:

    • PA=100W,
    • PB=25W.

    RARB=25100=14\frac{R_A}{R_B} = \frac{25}{100} = \frac{1}{4}​​

    Thus, the ratio of resistance of bulb A to that of bulb B is 1:4.

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