Two bells ring at intervals of 88 seconds and 58 seconds. If they both ring at 10 O'clock in the morning together, after how many seconds will they ring together again?

Correct option is A

Ans. (A)
Sol. To find when the bells will ring together again, we need to find the least common multiple (LCM) of the two intervals, 88 seconds and 58 seconds.
1. First, find the prime factorization of 88 and 58:
· 88 = 2^3 × 11
· 58 = 2 × 29
2. Now, find the LCM by taking the highest powers of each prime factor:
· LCM = 2^3 × 11 × 29 = 8 × 11 × 29 = 2552 seconds
Therefore, the two bells will ring together again after 2552 seconds.