Three of the following four letter-clusters are alike in a certain way and one is different. Pick the odd one out.

(NOTE: The odd one out is not based on the number of vowels or consonants in the word)​​

Logic: 1st letter + 4th letter = 24 
2nd letter + 3 = 3rd letter

A) Q I L G

Q + G → 24

I +  3 → L 

B) P J M H

P + H → 24

J + 3→ M 

C) U E D C

U + C → 24

E +  3→ F $$\neq$$ D​

D) S G J E

S + E → 24

G + 3→J

So option (C) is odd one out.

Thus, correct option is (c).