Three numbers which are co-prime to each other are such that the product of the first two numbers is 143 and that of the last two numbers is 195. The sum of the three numbers is________

Correct option is B

Given:

x ≤ y ≤ z (co-prime to each other)

x × y = 143

y × z = 195

Concept Used:

Co-prime numbers have no common factors other than 1.

Using the properties of products and divisors, deduce x, y, and z.

Solution:

x × y = 143

Factors are 143=11×13

So, x = 11 , y = 13(since x ≤ y).

y × z = 195

Factors are 195 = 13 × 15

So, y = 13, z = 15

Thus,

x + y + z = 11 + 13 + 15 = 39