What is the highest power of 3 in the prime factorisation of 234 ?

Correct option is D

.Given:

The number is 234.

Formula Used:

To find the highest power of a prime p in the prime factorization of a number n , we use the following method:

1. Divide n by p repeatedly until it is no longer divisible.

2. The highest power is the number of times n is divisible by p .

Solution:

1. Divide 234 by 3:

​$$234 \div 3 = 78$$​

2. Divide 78 by 3:

​$$78 \div 3 = 26$$​

3. Divide 26 by 3: 26 is not divisible by 3.

Thus, 234 can be written as:

​$$234 = 3^2 \times 26$$​

Final Answer:

The highest power of 3 in the prime factorization of 234 is $$3^2$$​ .

Final Answer:

Option D) 2