Three numbers are in the ratio 5 : 4 : 3, and their LCM is 4980. Their HCF is:

Correct option is B

Given:

Three numbers are in the ratio 5 : 4 : 3

LCM  =  4980

Formula Used:

LCM × HCF = Product of the numbers

Solution: ​

The LCM of 5, 4, 3 is calculated by finding the highest powers of the prime factors:

5 = 5¹

4 = 2²

3 = 3¹

Thus,

LCM(5, 4, 3) = $$2^2 \times 3^1 \times 5^1$$ = 60

Therefore,

LCM of (5H,4H,3H) = 60H

60H = 4980

H = $$\frac{4980}{60}$$​ = 83