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    What is the greatest number that, when it divides 1128, 1537 and 1834 leaves remainders 7, 3 and 5, respectively?
    Question

    What is the greatest number that, when it divides 1128, 1537 and 1834 leaves remainders 7, 3 and 5, respectively?

    A.

    43

    B.

    54

    C.

    59

    D.

    67

    Correct option is C

    Given:
    Numbers: 1128, 1537, 1834
    Remainders: 7, 3, 5 respectively
    Formula Used:
    Required greatest number (N) = HCF of (1128 - 7, 1537 - 3, 1834 - 5)
    Solution:
    Subtract remainders from the numbers
    1128 - 7 = 1121
    1537 - 3 = 1534
    1834 - 5 = 1829
    HCF of 1121, 1534, and 1829
    Prime factorization:
    1121 = 59 × 19
    1534 = 2 × 13 × 59
    1829 = 31 × 59
    => The greatest number = 59

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