Three identical bulbs are connected in parallel to a battery of 6 V. If the current in the circuit is 0.6 A, the power dissipated by the battery is:

Correct option is B

The correct option is (B) 3.6W

Information booster:

To calculate the power dissipated by the battery, we use the formula for electrical power:

$$P=V\times I$$

where:

• $P$ is the power,
• $V$ is the voltage of the battery,
• $I$ is the total current in the circuit.

Given:

• $V=6\text{V}$,
• $I=0.6\text{A}$.

Solution: 

$$P=6\text{V}\times 0.6\text{A}=3.6\text{W}.$$

Answer:

The power dissipated by the battery is 3.6 watts (W).