In an electrical circuit, five identical bulbs are connected in parallel to each other to a battery of 20" " V (negligible internal resistance). When all the five bulbs glow, a current of 5" " A is recorded. Then the power dissipated in the circuit and the resistance of each bulb are ___ and _____ , respectively.

Correct option is D

Here's the solution:

1. Power Calculation:

   • In a parallel circuit, the total power is the sum of the power dissipated by each bulb.
   • Power (P) = Voltage (V) * Current (I)
   • P = 20 V * 5 A = 100 W

2. Resistance Calculation:

   • In a parallel circuit with identical bulbs, the voltage across each bulb is the same as the battery voltage.
   • The total current is divided equally among the bulbs. So, the current through each bulb is 5 A / 5 = 1 A.
   • Resistance (R) = Voltage (V) / Current (I)
   • R = 20 V / 1 A = 20 Ω

Therefore, the correct answer is D) 100 W, 20 Ω