Three bells ring at intervals of 12 minutes, 18 minutes, and 24 minutes,respectively. If they all ring together at 12:00 p.m., In how many minuteswill they all ring together again?

Correct option is C

​Given:

The intervals at which the bells ring are 12 minutes, 18 minutes, and 24 minutes

Solution:

Prime factorization

12 = $$2^2 \times 3$$​​

18 =$$2 \times 3^2$$​​

24 = $$2^3 \times 3$$​​

LCM(12,18,24) = $$2^3 \times 3^2 = 8 \times 9$$​ = 72

So,

Thus, the bells will all ring together again after 72 minutes.