Correct option is B
Given:
Two gas parcels (A and B)
Same volume, temperature, and pressure
Parcel A:1 mole of water vapour (H₂O)
Parcel B:1 mole of dry air
Concept Used:
At the same temperature and pressure, the mass of one mole of a gas is simply its molar mass.
Molar mass of water vapour (H₂O) = 18 g/mol
Molar mass of dry air (approximate) = 78% N₂ (28 g/mol) + 21% O₂ (32 g/mol)
→ Weighted average ≈ 29 g/mol
Solution:
Parcel A (water vapour): 18 g
Parcel B (dry air): 29 g
So, Parcel B is heavier than Parcel A
Correct Option: (B) Parcel B is heavier than Parcel A