The value of $$(x+y)^2+(x-y)^2$$​​

Correct option is B

Solution:

$$(x + y)^2 = x^2 + 2xy + y^2,\\(x - y)^2 = x^2 - 2xy + y^2.\\\text {Now, add the two expansions:}\\(x + y)^2 + (x - y)^2 = (x^2 + 2xy + y^2) + (x^2 - 2xy + y^2).\\ (x + y)^2 + (x - y)^2 = 2x^2 + 2y^2.\\$$​

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