Correct option is BGiven: 55+55+410+15\frac{5}{5} + \frac{5}{5} + \frac{4}{10} + \frac{1}{5}55+55+104+51 - 2 Solution: 55+55+410+15\frac{5}{5} + \frac{5}{5} + \frac{4}{10} + \frac{1}{5}55+55+104+51 - 2 55+55+410+15−2 =115+410−2 =22+4−2010 =610\frac{5}{5} + \frac{5}{5} + \frac{4}{10} + \frac{1}{5}-2 \\ \ \\ = \frac{11}{5}+\frac{4}{10}-2 \\ \ \\ =\frac{22 + 4 - 20}{10} \\ \ \\ = \frac{6}{10} 55+55+104+51−2 =511+104−2 =1022+4−20 =106