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​The value of  53−02+(84)2−6+6×5=5^3-0^2+(\frac 84)^2-6+6 \times 5 = 53−02+(48​)2−6+6×5=​__________
Question

​The value of  5302+(84)26+6×5=5^3-0^2+(\frac 84)^2-6+6 \times 5 = ​__________

A.

153

B.

152

C.

154

D.

151

Correct option is A

Given:​
5302+(84)26+6×55^3-0^2+(\frac 84)^2-6+6 \times 5  
Solution:5302+(84)26+6×5=1250+46+30=125+4+306=1535^3-0^2+(\frac 84)^2-6+6 \times 5 \\= 125 - 0 + 4 - 6 + 30 \\= 125 + 4+ 30 - 6 \\= 153

5302+(84)26+6×5=1250+46+30=125+4+306=1535^3-0^2+(\frac 84)^2-6+6 \times 5 \\= 125 - 0 + 4 - 6 + 30 \\= 125 + 4+ 30 - 6 \\= 153

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