The value of 40 - 3 × [ 10 + 6 × { 20 - 10 ( 6 - 5 ) × 2} ÷ 47] is:

Correct option is D

Given:
 40 - 3 × [ 10 + 6 × { 20 - 10 ( 6 - 5 ) × 2} ÷ 47]
Concept Used:
​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline \text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline \end{array}$$​​
Solution:
 40 - 3 × [ 10 + 6 × { 20 - 10 ( 6 - 5 ) × 2} ÷ 47 
= 40 - 3 × [ 10 + 6 × { 20 - 10 × 2} ÷ 47] 
= 40 - 3 × [ 10 + 6 × { 20 - 20} ÷ 47] 
= 40 - 3 × [ 10 + 6 × 0  ÷ 47] 
= 40 - 3 × [ 10 + 6 × 0] 
= 40 - 3 × [ 10 +0 ] 
= 40 - 3 × [10] 
= 40 - 30
= 10