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The value of 326−3−436−2−68−12\frac{3\sqrt2}{\sqrt6-\sqrt3}-\frac{4\sqrt3}{\sqrt6-\sqrt2}-\frac{6}{\sqrt8-\sqrt{12}}6​−3​32​​−6​−2​43​​−8​−12​6​​
Question

The value of 326343626812\frac{3\sqrt2}{\sqrt6-\sqrt3}-\frac{4\sqrt3}{\sqrt6-\sqrt2}-\frac{6}{\sqrt8-\sqrt{12}}​ is:

A.

3+2{\sqrt3}+{\sqrt2}​​

B.

32{\sqrt3}-{\sqrt2}​​

C.

53{5}{\sqrt3}

D.

1

Correct option is C

​Given:

326343626812\frac{3\sqrt{2}}{\sqrt{6} - \sqrt{3}} - \frac{4\sqrt{3}}{\sqrt{6} - \sqrt{2}} - \frac{6}{\sqrt{8} - \sqrt{12}}​​

Solution:

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