The value of [3÷5-8 of 4+3×{8÷2-(4+3)}] is:

Correct option is D

Given:

​[3÷5-8 of 4+3×{8÷2-(4+3)}]   

Solution:  

[3÷5-8 of 4+3×{8÷2-(4+3)}] 

= [3÷5-32+3×{4-7}]

  $$[\frac{3}{5}-32+3×{(4-7)}]\\\ \\ = \frac{3}{5}-32+3×{-3} \\\ \\ = \frac{3}{5}-32-9\\\ \\= \frac{3}{5}- 41\\\ \\ = \frac{3 - 205}{5}\\\ \\ = \frac{-202}{5}$$​