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The value of 3−25÷[12÷4×2−(3×7÷21)]3 - 25 \div [12 \div 4 \times 2 - (3 \times 7 \div 21)]3−25÷[12÷4×2−(3×7÷21)] is:​
Question

The value of 325÷[12÷4×2(3×7÷21)]3 - 25 \div [12 \div 4 \times 2 - (3 \times 7 \div 21)] is:​

A.

-2

B.

-1

C.

1

D.

2

Correct option is A

Given: 

325÷[12÷4×2(3×7÷21)]3 - 25 \div [12 \div 4 \times 2 - (3 \times 7 \div 21)] 

Concept Used: 

BODMAS rule;

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}  

Solution: 

325÷[12÷4×2(3×7÷21)] =325÷[12÷4×2(1)] =325÷[5] =35 =23 - 25 \div [12 \div 4 \times 2 - (3 \times 7 \div 21)] \\ \ \\ = 3 - 25 \div [12 \div 4 \times 2 - (1)]\\ \ \\ = 3 - 25 \div [5]\\ \ \\ = 3 - 5 \\ \ \\ = -2​​

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