The two hands of a clock will be together between 7 AM and 8 AM at:

Correct option is B

When minute & hour hands coincide, then θ = 0
Here H = 7. Hands will be together at

$$θ = (30H - \frac{11}{2} M)\\ \\=> 0 = 30 × 7 - \frac{11}{2} M\\ \\=> 0 = 210 - \frac{11}{2} M\\ \\=> M = \frac{420}{11} M\\$$​
$$\frac{60}{11}H$$​minutes past 7
= $$\frac{(60 × 7)}{11}$$​minutes past 7
= $$\frac{420}{11}$$​ minutes past 7
= $$38\frac{2}{11}$$​minutes past. 7 AM.