The synchronous speed of an induction motor is 1,000 RPM. Find the percentage slip if its actual rotation speed is 980 RPM?

Correct option is A

​​$$\text{The formula for percentage slip } (S) \text{ in an induction motor is:} S = \frac{N_s - N_r}{N_s} \times 100$$

$$\textbf{Where:} \begin{array}{ll}\bullet \quad N_s = \text{Synchronous speed (1,000 RPM)} \\\bullet \quad N_r = \text{Rotor speed (980 RPM)}\end{array}$$​​​

​$$\text{Substitute the given values:}$$

$$S = \frac{1000 - 980}{1000} \times 100$$

$$S = \frac{20}{1000} \times 100$$

$$S = 2\%$$​​​​​