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The surface areas of two spheres are in the ratio 25 : 36. What is the ratio of their volumes?
Question

The surface areas of two spheres are in the ratio 25 : 36. What is the ratio of their volumes?

A.

2536\frac{25}{36}​​

B.

36115\frac{36}{ 115}​​

C.

125216\frac{125}{216}​​

D.

36125\frac{36}{ 125}​​

Correct option is C

Given:
Surface area of two sphere ratio 25 : 36 .
Concept Used:
Surface Area of Sphere = 4πr24π r^2​​
Volume of Sphere = (4π)3r3 \frac{(4π )}{3} r^3​​
Solution:
Let the two Sphere are S1 and S2 .
Radius of  S1=r1S_1 = r_1​ , Radius of S2=r2,S_2 = r_2,​​
Now, ratio of surface area of two spheres = (4πr12)(4πr22) \frac{(4π r_1^2)}{(4π r_2^2 )}​​
S1S2=4πr124πr222536=4πr124πr222536=r12r222536=r1r2r1r2=56.\begin{aligned}&\frac{S_1}{S_2} = \frac{4\pi r_1^2}{4\pi r_2^2} \\&\frac{25}{36} = \frac{4\pi r_1^2}{4\pi r_2^2} \\&\frac{25}{36} = \frac{r_1^2}{r_2^2} \\&\sqrt{\frac{25}{36}} = \frac{r_1}{r_2} \\&\frac{r_1}{r_2} = \frac{5}{6}.\end{aligned}​​
Now,
Ratio of volume,
S1S2=4π3r134π3r23S1S2=r13r23S1S2=5363S1S2=125216.\begin{aligned}&\frac{S_1}{S_2} = \frac{\frac{4\pi}{3} r_1^3}{\frac{4\pi}{3} r_2^3} \\&\frac{S_1}{S_2} = \frac{r_1^3}{r_2^3} \\&\frac{S_1}{S_2} = \frac{5^3}{6^3} \\&\frac{S_1}{S_2} = \frac{125}{216}.\end{aligned}​​

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