The sum of three consecutive multiples of 9 is 2457. Find the largest one.

Correct option is A

Given:

The sum of three consecutive multiples of 9 is 2457.

Solution:-

​Let the three consecutive multiples of 9 be:

​$$9x, \ 9(x+1), \ 9(x+2)$$​​

According to the question;

So, the largest multiple is $$9(x+2) = 9(90+2) = 9 \times 92 = \bf828$$​​