The sum of the digits of the minimum number by which 1800 is multiplied to get a perfect cube number is:

Correct option is B

Step 1: Prime Factorization of 1800
1800 = 2 x 2 x 2 x 3 x 3 x 5 x 5 = 2³ x 3² x 5²
Step 2: Determine the missing factors for a perfect cube
To make 1800 a perfect cube, we need to multiply it by factors that will make the exponents of each prime factor a multiple of 3.
2³ is already a perfect cube.
3² needs to be multiplied by 3 to become 3³.
5² needs to be multiplied by 5 to become 5³.
Step 3: Calculate the minimum multiplier
The minimum multiplier is 3 x 5 = 15.
Step 4: Find the sum of the digits of the multiplier
Sum of digits of 15 = 1 + 5 = 6.