The sum of a two-digit number and the number obtained by reversing the digits is 99. If the digits of the number differ by 7, then the two-digit number can be:
Given:
The sum of the two-digit number and the number obtained by reversing the digits is 99.
The digits of the number differ by 7
Solution:
Let the unit digit be x and tens digit be y
y - x = 7 ........(1)
From the first condition:
10y + x + (10x + y) = 99
11y + 11x = 99
y + x = 9 ..........(2)
Subtracting (1) from (2)
y + x -(y-x) = 9 - 7
2x = 2
x = 1
then y = 8
Thus the number be 81
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