The standard deviation of 12 values is 3. If each value is increased by 4, then find the variance of the new set of values.
Given:
Standard deviation of 12 values = 3
Each value is increased by 4
We are to find the variance of the new set
Concept Used:
Adding/subtracting a constant to all values does not change the standard deviation or variance.
Variance = (Standard Deviation)²
Solution:
Variance = 32 = 9
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