The smallest number which, when divided by 36 and 45 leaves remainders 8 and 17,respectively, is:

Correct option is C

Given:

First divisor a = 36

First remainder x = 8

Second divisor b = 45

Second remainder y = 17

Solution:

Now,  

Difference between divisor and remainder

d1 = 36 - 8 = 28

d2 = 45 - 17 = 28

Both differences are equal, 

LCM of 36 and 45 = 180

Thus, the smallest number

Number = 180 - 28 =152

Therefore, the smallest number which, when divided by 36 and 45, leaves remainders 8 and 17 respectively, is 152