The smallest number that can be divided exactly by 16, 18, 27 and 45 is:

Correct option is B

Given:

We are asked to find the smallest number that can be divided exactly by 16, 18, 27, and 45.

Solution:

16 = $$2^4$$​​

18 = $$2 \times 3^2$$​​

27 =$$3^3$$​​

45 =$$3^2 \times 5$$​​

The highest power of 2 is $$2^4$$​ from 16.

The highest power of 3 is $$3^3$$​ from 27.

The highest power of 5 is $$5^1$$​ from 45.

LCM = $$2^4 \times 3^3 \times 5^1 = 16 \times 27 \times 5 = 2160$$​