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    The smallest natural number which is divisible by 5, 10, 49 and 28 is:
    Question

    The smallest natural number which is divisible by 5, 10, 49 and 28 is:

    A.

    980

    B.

    1040

    C.

    900

    D.

    1006

    Correct option is A

    Given:
    Numbers given for divisibility: 5, 10, 49, and 28.
    Formula Used:
    Smallest number divisible by multiple numbers is their Least Common Multiple (LCM).
    Solution:
    5 = 5
    10 = 2 × 5
    49 = 72
    28 = 2 × 2 × 7
    LCM includes the highest power of all prime factors:
    LCM = 22 × 5 × 72 = 20 × 49 = 980

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