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The smallest natural number which is divisible by 5, 10, 49 and 28 is:
Question

The smallest natural number which is divisible by 5, 10, 49 and 28 is:

A.

980

B.

1040

C.

900

D.

1006

Correct option is A

Given:
Numbers given for divisibility: 5, 10, 49, and 28.
Formula Used:
Smallest number divisible by multiple numbers is their Least Common Multiple (LCM).
Solution:
5 = 5
10 = 2 × 5
49 = 72
28 = 2 × 2 × 7
LCM includes the highest power of all prime factors:
LCM = 22 × 5 × 72 = 20 × 49 = 980

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