Given:
Numbers: 33, 72, 11, 18
Formula Used:
LCM (Least Common Multiple) = Product of highest powers of all prime factors involved.
Solution:
Prime factorization:
33 = 3 × 11
72 = 2³ × 3²
11 = 11
18 = 2 × 3²
LCM = 2³ × 3² × 11 = 8 × 9 × 11 = 792
Therefore, the smallest natural number divisible by 33, 72, 11 and 18 is 792.
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60 Mins English English25 Questions50 Marks15 Mins English English100 Questions200 Marks60 Mins EnglishFind the smallest number which when increased by 20 is completely divisible by 12, 20, 15, 18 and 24.
Three bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ring simultaneously at 8:00 am. They will ring simultaneously again at
Three bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ringsimultaneously at 8: 00 am. They will ring simultaneously again at :
The largest four-digit number which when divided by 9, 18 and 23, leaves a remainder 5 in each case, is:
The LCM of 26, 34, 221 and 195 is:
The LCM of two numbers is 105 and numbers are in ratio 5 : 3. Find sum of numbers.
The LCM of 44, 32, 176 and 352 is:
The LCM of 46, 68, 136 and 138 is:
The LCM of 42, 36, 312 and 126 is:
The LCM of 40, 20, 195 and 160 is:
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