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The smallest natural number which is divisible by 33, 72, 11 and 18 is:
Question

The smallest natural number which is divisible by 33, 72, 11 and 18 is:

A.

839

B.

696

C.

792

D.

881

Correct option is C

Given:
Numbers: 33, 72, 11, 18
Formula Used:
LCM (Least Common Multiple) = Product of highest powers of all prime factors involved.
Solution:
Prime factorization:
33 = 3 × 11
72 = 2³ × 3²
11 = 11
18 = 2 × 3²
LCM = 2³ × 3² × 11 = 8 × 9 × 11 = 792
Therefore, the smallest natural number divisible by 33, 72, 11 and 18 is 792.

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