The smallest natural number which is divisible by 11, 6, 55 and 9 is:

Correct option is B

Given:
The number must be divisible by: 11, 6, 55, and 9
Formula Used:
Smallest natural number divisible by multiple numbers = LCM (Least Common Multiple) of the given numbers
Solution:
Prime factorizations:
11 = 11
6 = 2 × 3
55 = 5 × 11
9 = 3²
​$$\text{LCM} = 2 \times 3^2 \times 5 \times 11= 2 \times 9 \times 5 \times 11= 18 \times 5 = 9090 \times 11 = 990$$​​
 990 is the smallest natural number divisible by 11, 6, 55, and 9