Given:
The number must be divisible by: 11, 6, 55, and 9
Formula Used:
Smallest natural number divisible by multiple numbers = LCM (Least Common Multiple) of the given numbers
Solution:
Prime factorizations:
11 = 11
6 = 2 × 3
55 = 5 × 11
9 = 3²
990 is the smallest natural number divisible by 11, 6, 55, and 9
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60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishThree bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ring simultaneously at 8:00 am. They will ring simultaneously again at
Three bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ringsimultaneously at 8: 00 am. They will ring simultaneously again at :
The largest four-digit number which when divided by 9, 18 and 23, leaves a remainder 5 in each case, is:
The LCM of 26, 34, 221 and 195 is:
The LCM of two numbers is 105 and numbers are in ratio 5 : 3. Find sum of numbers.
The LCM of 44, 32, 176 and 352 is:
The LCM of 46, 68, 136 and 138 is:
The LCM of 40, 20, 195 and 160 is:
The LCM of 42, 36, 312 and 126 is:
What is the highest number between 5000 and 5500, which when divided by 12,16 and 24, would leave a remainder 9?
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