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    The sides (in cm) of a right triangle are (x − 18), (x − 25) and x. Its area (in cm²) is:
    Question

    The sides (in cm) of a right triangle are (x − 18), (x − 25) and x. Its area (in cm²) is:

    A.

    1329

    B.

    1314

    C.

    1311

    D.

    1320

    Correct option is D

    Given:

    The sides of a right triangle are (x - 18) cm, (x - 25) cm, and x cm.

    Formula Used:

    Pythagorean theorem:

    H2=P2+B2H^2 = P^2 + B^2​​

    Area of a right triangle:

    Area = 12×Base×Perpendicular \frac{1}{2} \times \text{Base} \times \text{Perpendicular}​​

    Solution:

    Using the Pythagorean theorem for this right triangle:

    x2=(x18)2+(x25)2x^2 = (x - 18)^2 + (x - 25)^2​​

    (x18)2=x236x+324(x - 18)^2 = x^2 - 36x + 324​​

    (x25)2=x250x+625(x - 25)^2 = x^2 - 50x + 625​​

    x2=(x236x+324)+(x250x+625)x^2 = (x^2 - 36x + 324) + (x^2 - 50x + 625)​​

    x2=2x286x+949x^2 = 2x^2 - 86x + 949​​

    x286x+949=0x^2 - 86x + 949 = 0​​

    (x - 13)(x - 73) = 0

    x = 13(not valid)

    x = 73.

    Now, 

    If x=73x = 73:

    Perpendicular: x - 18 = 73 - 18 = 55 cm

    Base: x - 25 = 73 - 25 = 48 cm

    Area  = 12×48×55=24×55=1320 cm2\frac{1}{2} \times 48 \times 55 = 24 \times 55 = 1320 \, \text{cm}^2​​

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