The sides a, b and c of a ΔΑΒC satisfy the equation (a-8)² + (b-15)² + (c - 17)² = 0. Then ∆ABC is

Correct option is B

Given:

Given sides of Δ ABC are a, b, c respectively.
Given the sides satisfy the equation 
(a – 8)²+ (b - 15)²+ (c - 17)²= 0.
Concept:
Square of a number is always non-negative.
In a right-angled triangle, the square of the largest side equals to the sum of the squares of the other two sides. 
Solution:
Given sides of Δ ABC are a, b, c respectively.
Given the sides satisfy the equation 
(a – 8)² + (b - 15)² + (c - 17)² = 0.
The square of a number is non-negative.
For the sum of the non-negative numbers to be zero, each number should be zero.
∴ a - 8 = 0 , b - 15 = 0 and c - 17 = 0.
=> a = 8, b = 15, c = 17.
We can find that 172 = 82 + 152

Or c² = a² + b².
∴ Δ ABC is a right-angled triangle.