The ratio of speed of P to speed of Q is 5:8, P covers D km distance in 3 hours and Q covers (D+40) km in 2.5 hours. If P increases his speed by 25%, then find the time taken by P to cover (D+180) km distance. (In hours)
Let the speed of P and Q be 5x kmph and 8x kmph respectively.
ATQ,
D=3×5x=15x ……..(I)
Also, D+40=2.5×8x
D=20x-40 …………..(II)
Solving (I) and (II),
15x=20x-40
x=8
So, D=15x=120 km
Original speed of P=5x=40 kmph
Required time
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