The ratio of present age of A to B’s is 3 : 2. Five years ago, A age was twice than that of B age at that time. Five years hence, sum of ages of A and B is equal to C age at that time. Find present age of C (in years)?

Correct option is E

Information given:
The ratio of present age of A to B’s is 3 : 2
Five years ago, A age was twice than that of B age at that time
Five years hence, sum of ages of A and B is equal to C age at that time
Explanation:
Let present age of B = x
Present age of A = 1.5x
B age five years ago = x – 5
A age five years ago = 2(x-5) = 2x – 10
But A age five years ago also equals to (1.5x – 5)
2x – 10 = 1.5x – 5
0.5x = 5
x = 10
C age five years hence = 10 + 5 + 1.5 × 10 + 5
= 15 + 15 + 5
= 35
C present age = 35 – 5 = 30 years