The product of the LCM and HCF of two numbers is 48 . If the two numbers differ by 13 , then find the numbers.

Correct option is A

Given :

HCF $$\times$$ LCM =  48 

Two number difference = 13

Formula used : ​

$$HCF \times LCM = Product \ of number$$​

Solution: 

Let the two number be x and y.

$$x \times y = 48$$ 

$$x - y = 13 (given)$$ 

Factors of x and y = 48 are ( 1, 48), (2, 24), (3, 16), (4, 12), (6, 8)

This only pair which satisfies both the condition is  (3, 16) 

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