The price of fuel decreases by 25%, 35% and 40% in three successive months, but increases by 60% in the fourth month. What is the percentage increase/decrease in the price of fuel in the fourth month as compared to its original price?

Correct option is B

Given:

The price of fuel decreases by 25%, 35%, and 40% in three successive months.

The price increases by 60% in the fourth month.

We need to find the percentage change in the price of fuel in the fourth month compared to its original price.

Formula Used:

Percentage change = $$\left( \frac{\text{Final price}}{\text{Original price}} - 1 \right) \times 100$$​​

Solution:  ​

Let the initial Price be 100 

Final price = $$100 \times (1 - \frac{25}{100}) \times (1 - \frac{35}{100}) \times (1 - \frac{40}{100}) \times (1 + \frac{60}{100})$$ 

​$$=100 \times (\frac{75}{100}) \times ( \frac{65}{100}) \times ( \frac{60}{100}) \times ( \frac{160}{100}) \\ \ \\ = 46.8$$​

Percentage change = $$\left( \frac{46.8}{100}-1\right)\times100 =-53.2\%$$​​

Thus, the overall percentage change in the price of fuel after the four months is a decrease of 53.2% compared to its original price.