The price of fuel decreases by 25%, 10% and 30% in three successive months, but increases by 60% in the fourth month. What is the percentage increase/decrease in the price of fuel in the fourth month as compared to its original price?

Correct option is C

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Given:
Successive changes in fuel price over four months:
1st month: Decrease by 25%
2nd month: Decrease by 10%
3rd month: Decrease by 30%
4th month: Increase by 60%
Formula Used:

If price changes successively by percentages a%, b%, c%…, then final value =
​$$P \times (1 + \frac{a}{100}) \times (1 + \frac{b}{100}) \times (1 + \frac{c}{100}) \ldots$$​​

Solution:
Let original price = ₹100

After 1st month: ₹100 × 0.75 = ₹75

After 2nd month: ₹75 × 0.90 = 67.5

After 3rd month: ₹67.5 × 0.70 = ₹47.25

After 4th month: ₹47.25 × 1.6 = ₹75.6

Final price = ₹75.6
Change from original = ₹100 - ₹75.6 = 24.4

Percentage change = $$\frac{-24.4}{100} \times 100$$ = -24.4%

24.4% decrease compared to the original price.