The present ages of A and B are in the ratio of 7 : 6. Eight years hence, the ratio of their ages will be 8 : 7. Find the present age of B.
Given:
Ratio of present ages of A and B = 7 : 6
Ratio of their ages after 8 years = 8 : 7
Formula Used:
Solution:
Let the present ages of A and B be 7x and 6x respectively.
Formulate the equation based on their ages after 8 years:
49x + 56 = 48x + 64
x = 8
Calculate the present age of B:
6 × 8 = 48
Final Answer
So the correct answer is (a)
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Suggested Test Series
Suggested Test Series
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The present ages of A and B are in the ratio of 7 : 6. Eight years hence, the ratio of their ages will be 8 : 7. Find the present age of B.
The father's age will be double his son's age after twenty years from now. If the father's age was seven times the son's age five years ago from now, then find their present ages (in years), respectively.
4 years ago, the age of son was 40% of his father's age. Father's present age is 44 years, then son's present age is (in years)
The ages of three siblings are x, 25, and 2x + 8 years, arranged in ascending order. The total ages of the youngest and the eldest is double the age of the third sibling. What is the age (in years) of the eldest?
The ages of Amit and Geeta are in the ratio 6: 5, and the sum of their ages is 44 years. Find Amit's age.
In 10 years from now, A will be twice as old as B was 10 years ago. If A is 9 years older than B, find the present age of A.
An uncle is 6 times as old as his nephew. In 6 years, the difference in their ages will be 30 years. What is the sum of their current ages (in years)?
