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4 years ago, the age of son was 40% of his father's age. Father's present age is 44 years, then son's present age is (in years)
Question

4 years ago, the age of son was 40% of his father's age. Father's present age is 44 years, then son's present age is (in years)

A.

16

B.

18

C.

20

D.

24

Correct option is C

Given:
Father's present age is 44 years.
4 years ago, the son's age was 40% of the father's age.

Formula Used:
Age n years ago = Present age - n
Present age = Age n years ago + n

Solution:
First, determine the father's age 4 years ago:
Fathers age 4 years ago=444Fathers age 4 years ago=40Father's\;age\;4\;years\;ago=44-4\\Father's\;age\;4\;years\;ago=40​​
According to the problem, the son's age 4 years ago was 40% of the father's age at that time.
Sons age 4 years ago=40%×40Sons age 4 years ago=40100×40Sons age 4 years ago=16Son's\;age\;4\;years\;ago=40\%\times40\\Son's\;age\;4\;years\;ago=\frac{40}{100}\times40\\Son's\;age\;4\;years\;ago=16​​
To find the son's present age, add 4 years to his age from 4 years ago:
Son's present age=16+4
$on's present age=20
The son's present age is 20 years.

Final Answer
So the correct answer is (c)

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