The population of a town is 10,000. If the male population increases by 5% and the female population by 10%, the population will become 10,800. How much of the town's present population is female?

​Total population of the town = 10,000

Male population increases by 5%

Female population increases by 10%

After the increase, the total population becomes 10,800. 

Concept Used: ​

Total increased population = Total increased in male population + total increased in female population 

total increased population = $$\text{Male or female population}\times \left( 1+\frac{\text{Percent increase}}{100}\right)$$  ​

Solution:
Let x be the male population of town and 10000-x be the female population of town
So, ATQ

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