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    ​The perimeter of a rectangle is 120 m. If its length is twice its breadth, then its area is: ​
    Question

    The perimeter of a rectangle is 120 m. If its length is twice its breadth, then its area is:

    A.

    500 m2500 \, \text{m}^2​​

    B.

    600 m2600 \, \text{m}^2​​

    C.

    700 m2700 \, \text{m}^2​​

    D.

    800 m2800 \, \text{m}^2​​

    Correct option is D

    Given:

    ​The perimeter of a rectangle is 120 m.

    If its length is twice its breadth.

    Formula used:

    Area = l × b

    Perimeter = 2 × (l + b)

    Where:

    A is the area of the rectangle.

    l is the length of the rectangle.

    b is the breadth of the rectangle.

    Solution:

    Let, Breadth of the rectangle = b 

    Then Length = 2b 

    Perimeter = 120

    2 × (2b + b) = 120

    (3b) = 1202\frac{120}{2}

    (b) = 20

    then, length = 40cm

    Now, rea of the rectangle.

    Area =  40 × 20

    Area = 800 m2\mathrm{m^2}​​

    Thus, option (d) is correct.

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