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The order of a leaf node in a B+ tree is the maximum number of (value, data record pointer) pairs it can hold. Given that the block size is 1K bytes,
Question



The order of a leaf node in a B+ tree is the maximum number of (value, data record pointer) pairs it can hold. Given that the block size is 1K bytes, data record pointer is 7 bytes long, the value field is 9 bytes long and a block pointer is 6 bytes long, what is the order of the leaf node?

A.

63

B.

64

C.

67

D.

68

Correct option is A


The order of a leaf node in a B+ tree refers to the maximum number of (value, data record pointer) pairs it can hold. Given the block size and the size of different fields, we calculate this as follows:
Data Given:
1. Block size: 1 KB = 1024 bytes
2. Value field size: 9 bytes
3. Data record pointer size: 7 bytes
4. Block pointer size: 6 bytes (used to point to the next leaf node for linked list structure).
Calculation:
1. Space per entry: Each (value, data record pointer) pair takes:

Information Booster
1. B+ Tree Overview:
· A B+ tree is a self-balancing tree data structure used for databases and file systems.
· Leaf nodes store (key, value) pairs or (key, pointer) pairs.
2. Order of B+ Tree:
· The order is determined by the size of keys, pointers, and the block size.
· Ensuring efficient disk access is crucial in choosing the block size.
3. Space Efficiency: In databases, larger blocks and smaller keys allow more entries in each node, reducing the height of the tree.
Additional Knowledge
· A leaf node must also store a pointer to the next leaf for sequential access.
· As the block size increases, the height of the B+ tree decreases, improving search time.
· Non-leaf nodes in a B+ tree store only keys and block pointers, not data pointers.

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