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The mean proportional between (9+45) and (18−85) is:\left(9 + 4\sqrt{5}\right) \text{ and } \left(18 - 8\sqrt{5}\right) \text{ is:
Question

The mean proportional between (9+45) and (1885) is:\left(9 + 4\sqrt{5}\right) \text{ and } \left(18 - 8\sqrt{5}\right) \text{ is:}

A.

5\sqrt{5}

B.

15\sqrt{15}​​

C.

17\sqrt{17}

D.

2\sqrt{2}

Correct option is D

Given:

 (9+45) and (1885)\left(9 + 4\sqrt{5}\right) \text{ and } \left(18 - 8\sqrt{5}\right)

Solution: 

Mean proportional of A and BAB\sqrt{AB}   

Solution: 

(9+45) and (1885)\left(9 + 4\sqrt{5}\right) \text{ and } \left(18 - 8\sqrt{5}\right)   

(9+45)(1885)\sqrt{\left(9 + 4\sqrt{5}\right) \left(18 - 8\sqrt{5}\right) } 

(9+45)×2(945)\sqrt{\left(9 + 4\sqrt{5}\right) \times 2\left(9- 4\sqrt{5}\right) } 

2(92(45)2)\sqrt{2\left(9^2 - (4\sqrt{5}\right)^2) } 

2×(8180)\sqrt{2\times (81- 80)} 

2\sqrt{2}​​

​​​

                                                


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