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    Find the mean proportional between (4+√5) and (12-2√20).
    Question

    Find the mean proportional between (4+√5) and (12-2√20).

    A.

    39\sqrt{39}​​

    B.

    2752\sqrt{7 - \sqrt{5}}​​

    C.

    75\sqrt{7 - \sqrt{5}}​​

    D.

    27+52\sqrt{7 + \sqrt{5}}​​

    Correct option is B

    Given:
    Find the mean proportional between (4 + √5) and (12 − 2√20).
    Formula Used:
    Mean Proportional between two numbers a and b = a×b \sqrt{a \times b}​​
    Solution:
    Let:
    a=(4+5),b=(12220)a = (4 + \sqrt{5}), \quad b = (12 - 2\sqrt{20})​​
    a×b=(4+5)(12220)\sqrt {a \times b} = \sqrt {(4 + \sqrt{5})(12 - 2\sqrt{20})} 
    20=25\sqrt{20} = 2\sqrt{5} ​​
    b=122×25=1245b = 12 - 2 \times 2\sqrt{5} = 12 - 4\sqrt{5} 
    Mean Proportional=(4+5)(1245)\text{Mean Proportional} = \sqrt {(4 + \sqrt{5})(12 - 4\sqrt{5})}​​
    Mean Proportional = 4×124×45+5×125×45\sqrt {4 \times 12 - 4 \times 4\sqrt{5} + \sqrt{5} \times 12 - \sqrt{5} \times 4\sqrt{5}}​​
    Mean Proportional=48165+1254×5Mean Proportional=484520Mean Proportional=2845Mean Proportional=275\text{Mean Proportional}= \sqrt {48 - 16\sqrt{5} + 12\sqrt{5} - 4 \times 5}\\\text{Mean Proportional}= \sqrt {48 - 4\sqrt{5} - 20}\\\text{Mean Proportional}= \sqrt {28 - 4\sqrt{5}}\\\text{Mean Proportional} = 2\sqrt {7-\sqrt 5}​​



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