The least number which should be added to 6424 so that the sum is exactly divisible by 8, 9 and 12 is:
Given:
Number = 6424
Divisors = 8, 9, 12
Solution:
Prime factors:
8 = 2 × 2 × 2
9 = 3 × 3
12 = 2 × 2 × 3
LCM = 2 × 2 × 2 × 3 × 3 = 72
6424 ÷ 72 = 89 remainder 16
Least number to be added = 72 – 16 = 56
Required number = 56
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