Correct option is A
Given:
The LCM of two positive integers = thrice the larger number
Difference between smaller number and HCF = 6
Formula Used:
LCM × HCF = a × b
Substitute the known values and solve.
Solution:
Let the two numbers be a (smaller) and b (larger)
LCM of the two = 3b
3b × HCF = a × b
3 × HCF = a…..(1)
Now,
a – HCF = 6
From(1)
3 × HCF – HCF = 6
2 × HCF = 6
HCF = 3
Now,
3 × 3 = a
a = 9