The LCM of 63, 36 and x is 252. Which of the following options CANNOT be a value of x?
Given:
LCM of 63, 36, and x is 252.
We are to find which option cannot be a value of x.
Solution:
If LCM(63, 36, x) = 252, and LCM(63, 36) = 252,
then x must be a factor of 252.
Prime factorization of 252:
252=
Now check each option:
A. 28 = → factors are in 252 → can be x
B. 42 = 2 × 3 × 7 → factors are in 252 → can be x
C. 14 = 2 × 7 → factors are in 252 → can be x
D. 56 = → 2³ exceeds 2² in 252 → LCM will increase → cannot be x
Answer: Option D (56)
English
100 Questions
100 Marks
90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishThree bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ring simultaneously at 8:00 am. They will ring simultaneously again at
Three bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ringsimultaneously at 8: 00 am. They will ring simultaneously again at :
The largest four-digit number which when divided by 9, 18 and 23, leaves a remainder 5 in each case, is:
The LCM of 26, 34, 221 and 195 is:
The LCM of two numbers is 105 and numbers are in ratio 5 : 3. Find sum of numbers.
The LCM of 44, 32, 176 and 352 is:
The LCM of 46, 68, 136 and 138 is:
The LCM of 40, 20, 195 and 160 is:
The LCM of 42, 36, 312 and 126 is:
What is the highest number between 5000 and 5500, which when divided by 12,16 and 24, would leave a remainder 9?
Suggested Test Series
Suggested Test Series
