The larger of two supplementary angles is 62° more than the smaller one. The smaller angle (in degree) is:
Given:
Two angles are supplementary;
The larger angle is 62° more than the smaller one;
Sum of supplementary angles is 180°.
Concept Used:
If two angles are supplementary, their sum is 180°.
Solution:
Smaller angle = x
Larger angle = x + 62
Now,
x + x + 62 = 180
2x + 62 = 180
2x = 180 - 62 = 118
x = = 59
Thus, smaller angle is 59o
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The larger of two supplementary angles is 60° more than the smaller one. The smaller angle (in degree) is:
The larger of two supplementary angles is 62° more than the smaller one. The smaller angle (in degree) is:
The lines L1 and L2 are parallel lines cut by a transversal. If the measure of one of the corresponding angles is 75°, then what is the measure of the other corresponding angle?
Let AB and CD be two parallel lines and PQ be a transversal such that PQ intersects AB at the point R and CD at the point S, respectively. If ∠BRP = (2x + 13)° and ∠DSP = (3x − 22)°, then find ∠CSP.