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The intensity of udl. which, when it acts over the entire span of 1 m of a cantilever beam of rectangular cross-section of width of 100 mm and depth 2
Question

The intensity of udl. which, when it acts over the entire span of 1 m of a cantilever beam of rectangular cross-section of width of 100 mm and depth 200 m, would produce a maximum shear stress of 1.5N/mm², is-

A.

30kN/m

B.

26.6kN/m

C.

20kN/m

D.

36.6kN/m

Correct option is C

Given: b=100 mm,d=200 mm,L=1 m=1000 mm,τmax=1.5 N/mm2.For a rectangular section: τmax=32VA,A=bd.A=100×200=20000 mm2.1.5=32V20000=>V=1.5×20000×23=20000 N.For a cantilever with UDL w (N/m) over L=1 m: Vmax=wL=w.w=V=20000 N=20000 N/m=20 kN/m.\text{Given: } b=100\ \text{mm},\quad d=200\ \text{mm},\quad L=1\ \text{m}=1000\ \text{mm},\quad \tau_{\max}=1.5\ \text{N/mm}^2.\\[6pt]\text{For a rectangular section: }\tau_{\max}=\frac{3}{2}\cdot\frac{V}{A},\quad A=b d.\\[6pt]A=100\times200=20000\ \text{mm}^2.\\[6pt]1.5=\frac{3}{2}\cdot\frac{V}{20000}\quad\Rightarrow\quad V=\frac{1.5\times20000\times2}{3}=20000\ \text{N}.\\[6pt]\text{For a cantilever with UDL }w\ (\text{N/m})\text{ over }L=1\ \text{m: }V_{\max}=wL=w.\\[6pt]w=V=20000\ \text{N}=20000\ \text{N/m}=20\ \text{kN/m}.​​

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